WebAnswer (1 of 2): The force that is taking the mass m=2kg down the inclined plane of 30 degree is = mg sin30-F Where g is acceleration due to the gravity (10m/sec^2) and F is the frictional force between the mass and the inclined plane. This results into an acceleration of a= 3m/sec^2 of the mas... WebMar 15, 2024 · Today, he’s one of more than 200,000 military service members and veterans suing the conglomerate. 3M stock, which hit a new 52-week low Wednesday, is one of the worst-performing industrial...
Technical Data Sheet 3M
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Technical Data Sheet 3M
WebSo the speed of the center of mass is equal to r times the angular speed about that center of mass, and this is important. This you wanna commit to memory because when a problem says something's rotating or rolling without slipping, that's basically code for V equals r omega, where V is the center of mass speed and omega is the angular speed ... Web87.A 50 meter vertical tower casts a 62.3 meters shadow when the angle of elevation of the sun is 41.6°. the inclination of the ground is: a. 4.33° b. 4.72° * c. 5.63° d. 5.17° b . 4.72 ° * Given: H (Height) = 50 m Shadow distance = 62.3m Angle of elevation = 41.6° Angle B is of 90° Solution: In Δ ABC AB = Height of tower BC = Shadow distance WebA block of mass 2 kg slides down an incline plane of inclination 30∘. The coefficient of friction between block and plane is 0.5. The contact force between block and incline plane is:A. 5 √7 NB. 5 √15 NС. 10 √3 ND. 25 N biology sinhala medium resource book